{VERSION 4 0 "IBM INTEL NT" "4.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 1 135 15 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Comment" 2 18 "" 0 1 63 135 1 0 0 0 0 0 0 0 0 0 0 1 }{CSTYLE "2D Output" 2 20 "" 0 1 0 0 255 1 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 1 }{PSTYLE "Normal " -1 0 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }0 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Output" 0 11 1 {CSTYLE "" -1 -1 "" 0 1 0 0 32 0 0 0 0 0 0 0 0 0 0 1 }3 3 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 11 12 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }1 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "Maple Plot" 0 13 1 {CSTYLE "" -1 -1 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }{PSTYLE "" 0 256 1 {CSTYLE "" -1 -1 "" 0 1 32 32 50 0 0 0 0 0 0 0 0 0 0 1 }3 0 0 -1 -1 -1 0 0 0 0 0 0 -1 0 }} {SECT 0 {EXCHG {PARA 256 "" 0 "" {TEXT 256 32 "Solution to a convectio n problem" }{TEXT -1 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 258 "As a n example of the the convection problem in lecture 15 consider a rod w hich is kept at temperature T(0,t)=0 at one end. We choose the initial rod temperature to be T(x,0)=0. At the other end (x=a) there is con vective contact with a fluid at temperature " }{XPPEDIT 18 0 "T[1]" "6 #&%\"TG6#\"\"\"" }{TEXT -1 33 ".The boundary condition at x=a is" }}} {EXCHG {PARA 0 "" 0 "" {XPPEDIT 18 0 "-kappa*diff(T(x,t),x) = h*(T(a,t )-T[1]);" "6#/,$*&%&kappaG\"\"\"-%%diffG6$-%\"TG6$%\"xG%\"tGF.F'!\"\"* &%\"hGF',&-F,6$%\"aGF/F'&F,6#F'F0F'" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 33 "The steady state solution is then" }}}{EXCHG {PARA 0 "" 0 "" {XPPEDIT 18 0 "T[S] = x*h*T[1]/(kappa+h*a);" "6#/&%\"TG6#%\"SG*&*(%\"x G\"\"\"%\"hGF+&F%6#F+F+F+,&%&kappaGF+*&F,F+%\"aGF+F+!\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 38 "The initial condition on the transient" } }}{EXCHG {PARA 0 "" 0 "" {XPPEDIT 18 0 "u(x,t)=T(x,t)-T[S]" "6#/-%\"uG 6$%\"xG%\"tG,&-%\"TG6$F'F(\"\"\"&F+6#%\"SG!\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 8 "is thus " }{XPPEDIT 18 0 "u(x,0)=-T[S]" "6#/-%\"uG6$% \"xG\"\"!,$&%\"TG6#%\"SG!\"\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 30 " The eigenvalue problem is thus" }}{PARA 0 "" 0 "" 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18 0 "(2*n-1)/(2*a)" "6#*&,&*&\"\"#\"\"\"%\"n GF'F'F'!\"\"F'*&F&F'%\"aGF'F)" }{TEXT -1 3 "..." }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 74 "i.e there is one eigenvalue in each interval when th e tangent goes from -" }{XPPEDIT 18 0 "infinity" "6#%)infinityG" } {TEXT -1 6 " to + " }{XPPEDIT 18 0 "infinity" "6#%)infinityG" }{TEXT -1 2 " ." }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 36 "Let us find the first 10 eigenvalues" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 7 "ne:=10;" }}{PARA 11 "" 1 "" {XPPMATH 20 "6#>%#neG\"#5" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 40 "f:=lambda->tan(lambda*a)+kappa*lambda/h;" }} {PARA 11 "" 1 "" {XPPMATH 20 "6#>%\"fGR6#%'lambdaG6\"6$%)operatorG%&ar rowGF(,&-%$tanG6#*&9$\"\"\"%\"aGF2F2*&*&%&kappaGF2F1F2F2%\"hG!\"\"F2F( F(F(" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 78 "s:=seq(fsolve(f(lam bda)=0,lambda=(2*n-3)*Pi/(2*a)..(2*n-1)*Pi/(2*a)),n=1..ne);" }}{PARA 12 "" 1 "" {XPPMATH 20 "6#>%\"sG6,$\"\"!F'$\"+UHPwy!#5$\"+Dcgr;!\"*$\" +&e8ih#F-$\"+YFb'e$F-$\"+Ya(F-$\"+ ti6P&)F-" 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approaches the steady state solution!" }}}}{MARK "28 0 0" 72 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }